[Octave-bug-tracker] [bug #57132] [octave forge] (control) step: size of output y is not same as the size of input t

[Doug Stewart]

Follow-up Comment #5, bug #57132 (project octave):

The problem arises from the fact that a vector of time values was given as
input to the step function, and then it is converted to a start time, end time
and a step value (dt). This is then passed on to some subfunction which
converts it back to a vector.

In this situation there are binary roundoff problems where numbers that should
be 0.01 are actually calculated to be 0.00999999999998

This then leads to having a different final vector length. 

I am trying to come up with the correct way to overcome this kind of problem.

Line 106 of __time_response__.m  is where it starts.

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