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Re: How to break out of a computation?
From: |
John W. Eaton |
Subject: |
Re: How to break out of a computation? |
Date: |
Mon, 20 Feb 2006 15:40:00 -0500 |
On 20-Feb-2006, Sebastien Loisel wrote:
| BTW, does the Windows implementation of std::cout mean that if you do
| > something like
| >
| > function_from_dll_one ("some output");
| > function_from_dll_two ("some other output");
| >
| > in which these functions both write to std::cout, but they are defined
| > in separate DLLs, that the order of output is not defined? I'm
|
|
| No idea.
I found an answer to a FAQ here
http://www.ocsystems.com/faqs/rc_aprobe_faq.html
(question 13.8) that seems to indicate yes. But this seems like a
strange place to find the answer to my question. Is this explained on
an MS web page somewhere? Perhaps along with a rationale about why it
is desirable and/or necessary for Windows?
jwe
- How to break out of a computation?, Sebastien Loisel, 2006/02/18
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/20
- Re: How to break out of a computation?, John W. Eaton, 2006/02/20
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/20
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/20
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/20
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/21
- Re: How to break out of a computation?, John Swensen, 2006/02/21
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/21
- Message not available
- Re: How to break out of a computation?, David Bateman, 2006/02/22
- Re: How to break out of a computation?, Sebastien Loisel, 2006/02/22