Re: evaluation order in matlab/octave

[Levente Torok]

On Saturday 27 September 2008, you wrote:
> On Sat, Sep 27, 2008 at 5:59 PM, Levente Torok <address@hidden> wrote:
> > Hi!
> >
> > The following expression runs differently on octave than on matlab:
> >
> > function z = f( par )
> >    if ( nargin==0 | isempty(par) )
> >        z=3;
> >    end
> > end
> >
> > Calling
> >        f;
> > results in differences.
> >
> > In matlab if the first part of the if statment is true, the second term is 
> > not evaluated hence it
> > runs fine.
> > In octave it raieses and error that par is not defined.
> > Is there a way to overcome this or it would cause too much work.
> >
> 
> You can simply use || and && in Octave.

Thanks but I was about to use a code written to matlab.
This is it.
L


-- 
Blogger of http://fapuma.blogspot.com