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Re: Bug when dividing a scalar by a vector?
From: |
Sebastian Schöps |
Subject: |
Re: Bug when dividing a scalar by a vector? |
Date: |
Thu, 12 Jan 2017 07:42:33 -0800 (PST) |
Montgomery-Smith, Stephen wrote
> My guess is that it is solving the underdetermined equation:
>
> x1+x2+x3+x4=1.
>
> So both solutions are correct answers. There are infinitely many correct
> answers.
>
> If I had to choose, I guess I would go for the answer who square sum is
> minimized, which would favor Octave's answer.
Thanks! That explains the behaviour and I agree that both solutions do make
sense. However, is that documented somewhere? Shouldn't there be a warning?
Similar to the case when a singular linear equation system is solved?
Sebastian
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- Bug when dividing a scalar by a vector?, Sebastian Schöps, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Montgomery-Smith, Stephen, 2017/01/12
- Re: Bug when dividing a scalar by a vector?,
Sebastian Schöps <=
- Re: Bug when dividing a scalar by a vector?, John W. Eaton, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Marco Caliari, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Sebastian Schöps, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Mike Miller, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Sebastian Schöps, 2017/01/12
- Re: Bug when dividing a scalar by a vector?, Ben Abbott, 2017/01/12