Re: line continuations

[José Abílio Matos]

On Wednesday, 19 February 2020 20.01.12 WET Nicholas Jankowski wrote:
> I think the strrep function is fine. c is a char array. the bug about how
> the array is stored is changing the shape of the array.  the substitution
> appears to be fine, if c was actually what you wanted (a two row char
> array). As stated in 'help char',   Matlab/Octave concatenates char arrays
> vertically (are stored columnwise). so the stored order is 1 4 2 5 3 6. eg:
> 
> octave:13> a=char('test1','test2')
> a =
> 
> test1
> test2
> 
> octave:14> a(1)
> ans = t
> octave:15> a(2)
> ans = t
> octave:16> a(:)
> ans =
> 
> t
> t
> e
> e
> s
> s
> t
> t
> 1
> 2

I am aware of this as well of the other variant:
>> a(1:end)
ans = tteesstt12

What I was trying to understand is if this result is an expected outcome or if 
it would be better to throw an error in this scenario (just like Matlab does).

The matrix of char is confusing and probably (and this is the degree of 
certainty that I am trying to determine) the user wanted instead to use the 
cell array version:

>> a = {'test1';'test2'}
>> strrep(a, 't', '-')
ans =
{
  [1,1] = -es-1
  [2,1] = -es-2
}

and this works the same in Octave and Matlab.

Regards,
-- 
José Matos