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From: | Dr. Oliver Walter |
Subject: | Re: Confidence interval is mathematically equivalent to hypothesis test |
Date: | Sun, 14 Oct 2018 10:07:09 +0200 |
User-agent: | Mozilla/5.0 (Windows NT 10.0; WOW64; rv:52.0) Gecko/20100101 Thunderbird/52.9.1 |
Am 14.10.2018 um 09:41 schrieb John Darrington:
Which is why I suggested using one of the CDF functions. There is no T function, but there is a F function, which I think is the same if you set DF2 to 1. But you probably know better than me about those details. Perhaps IDF.F (0.05, N -1, 1) is what Werner wants (I haven't tried it)?
Ok. I see. I think the t distribution is implemented in PSPP. IDF.T(0.975, n-1) gives the correct t value for a 95% CI. Werner could try it.
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