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[Qemu-devel] [PATCH v2 1/4] ahci: Do not ignore memory access read size
From: |
John Snow |
Subject: |
[Qemu-devel] [PATCH v2 1/4] ahci: Do not ignore memory access read size |
Date: |
Tue, 16 Jun 2015 12:02:52 -0400 |
The only guidance the AHCI specification gives on memory access is:
"Register accesses shall have a maximum size of 64-bits; 64-bit access
must not cross an 8-byte alignment boundary."
I interpret this to mean that aligned or unaligned 1, 2 and 4 byte
accesses should work, as well as aligned 8 byte accesses.
In practice, a real Q35/ICH9 responds to 1, 2, 4 and 8 byte reads
regardless of alignment. Windows 7 can be observed making 1 byte
reads to the middle of 32 bit registers to fetch error codes.
Introduce a wrapper to support unaligned accesses to AHCI.
This wrapper will support aligned 8 byte reads, but will make
no effort to support unaligned 8 byte reads, which although they
will work on real hardware, are not guaranteed to work and do
not appear to be used by either Windows or Linux.
Signed-off-by: John Snow <address@hidden>
---
hw/ide/ahci.c | 27 +++++++++++++++++++++++++--
1 file changed, 25 insertions(+), 2 deletions(-)
diff --git a/hw/ide/ahci.c b/hw/ide/ahci.c
index 9e5d862..26df2ca 100644
--- a/hw/ide/ahci.c
+++ b/hw/ide/ahci.c
@@ -331,8 +331,7 @@ static void ahci_port_write(AHCIState *s, int port, int
offset, uint32_t val)
}
}
-static uint64_t ahci_mem_read(void *opaque, hwaddr addr,
- unsigned size)
+static uint64_t ahci_mem_read_32(void *opaque, hwaddr addr)
{
AHCIState *s = opaque;
uint32_t val = 0;
@@ -368,6 +367,30 @@ static uint64_t ahci_mem_read(void *opaque, hwaddr addr,
}
+/**
+ * AHCI 1.3 section 3 ("HBA Memory Registers")
+ * Support unaligned 8/16/32 bit reads, and 64 bit aligned reads.
+ * Caller is responsible for masking unwanted higher order bytes.
+ */
+static uint64_t ahci_mem_read(void *opaque, hwaddr addr, unsigned size)
+{
+ hwaddr aligned = addr & ~0x3;
+ int ofst = addr - aligned;
+ uint64_t lo = ahci_mem_read_32(opaque, aligned);
+ uint64_t hi;
+
+ /* if < 8 byte read does not cross 4 byte boundary */
+ if (ofst + size <= 4) {
+ return lo >> (ofst * 8);
+ }
+ g_assert_cmpint(size, >, 1);
+
+ /* If the 64bit read is unaligned, we will produce undefined
+ * results. AHCI does not support unaligned 64bit reads. */
+ hi = ahci_mem_read_32(opaque, aligned + 4);
+ return (hi << 32 | lo) >> (ofst * 8);
+}
+
static void ahci_mem_write(void *opaque, hwaddr addr,
uint64_t val, unsigned size)
--
2.1.0