[Bug 1894029] Re: qemu-i386 malloc error

[Michael Tokarev]

Please stop asking questions using a bug tracking system, this is rude.

No it is not a bug, it appears you can't do simple arithmetics, -- the
pointer is increased by 16 bytes not 2.

** Changed in: qemu
       Status: New => Invalid

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https://bugs.launchpad.net/bugs/1894029

Title:
  qemu-i386 malloc error

Status in QEMU:
  Invalid

Bug description:
  Hi!I use qemu-i386-static on 64 bit machines.And memory request succeeded, 
but the pointer is wrong.
  This is my test program:

  #include <stdint.h>
  #include <stdio.h>
  #include <stdlib.h>
  #include <unistd.h>

  int main(int argc, char **argv)
  {
          void *pa=0,*pb=0,*pc=0,*pd=0;
          pa = malloc(sizeof(uint32_t));
          pb = malloc(sizeof(uint32_t));
          pc = malloc(4);
          pd = malloc(4);
          printf("pa: 0x%x\n",pa);
          printf("pb: 0x%x\n",pb);
          printf("pc: 0x%x\n",pc);
          printf("pd: 0x%x\n",pd);
          printf("uint32_t:%d\n",sizeof(uint32_t));
          free(pa);
          free(pb);
          free(pc);
          free(pd);
          return 0;
  }

  And it is wrong:

  pa: 0x400051a0
  pb: 0x400051b0
  pc: 0x400051c0
  pd: 0x400051d0
  uint32_t:4

  Why did I apply for 4 bytes of space, but the pointer only increased by 2 
bytes??
  Is it a BUG??

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