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[Taler] S, B, B^-1

From: fabian . kirsch
Subject: [Taler] S, B, B^-1
Date: Wed, 30 Sep 2015 15:06:12 +0200
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On the next to last page:

"S_K(.) and B_b(.) commute" i don't think that is true..

and unblinding is not the inverse of blinding (at least in RSA).

All that is given is: U(S(B(X))) = S(X)
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