Re: [Tinycc-devel] Strange sizeof construct

[Fred Weigel]

Marc

sizeof is an operator

arr evaluates to the base of the array. [] is an operator.

since arr is the base of the array, (arr) is the same value (putting
in the parentheses doesn't change a thing). The precedence is identical!

so, if "sizeof arr[0]" works, then "sizeof (arr) [0]" should be identical.
Since [] is higher precedence, "sizeof(arr[0])" is ALSO the same. And,
just for grins, try:

sizeof((arr)[0])

Of course, this is because [] is an operator in C, and not part of a
variable construct. This means that any [] can be applied to any pointer.