Re: [Tinycc-devel] simple #ifdef causes "error: function pointer expected"

[Massimo Sala]

I read about this topic.

Arnold wrote:

    This isn't valid C. The preprocessor doesn't know about sizeof.

I found this:

    C99 doesn't require support for "sizeof" in preprocessor conditionals and gcc for example doesn't support it.

Indeed this snippet compiles and run like a charm:

int main()
{
#define big sizeof(size_t)
printf("big boss %zd\n", big);
return 0;
}

Any suggestion how to check with macro the sizeof size_t ?

Should I check the max value of a size_t to infer its size ?

M

On Thu, 21 May 2020 at 14:17, Massimo Sala <address@hidden> wrote:

Ops.

Pls any suggestion how to check with macro the sizeof size_t ?

Should I check the max value of a size_t to infer its size ?

I cannot find how to.

M

On Thu, 21 May 2020 at 14:08, <address@hidden> wrote:

This isn't valid C. The preprocessor doesn't know about sizeof.

Arnold

Massimo Sala <address@hidden> wrote:

> Hi
>
> Compiling the attached sample, tcc bails out with "error: function pointer
> expected"
> Pls, how can I fix ?
> Best regards, Massimo
>
> #include <stdio.h>
> #include <stdlib.h>
> #include <string.h>
>
> int main()
> {
> printf("ciao\n");
> #if sizeof(size_t) == 64
> printf("big boss\n");
> #endif
> return 0;
> }