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Re: [Groff] \(bu in groff_char.7
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From: |
Tadziu Hoffmann |
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Subject: |
Re: [Groff] \(bu in groff_char.7 |
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Date: |
Wed, 17 Jun 2015 18:19:34 +0200 |
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User-agent: |
Mutt/1.5.21 (2010-09-15) |
> The man page says that \(bu has unicode U+2022, but nroff puts
> out U+00b7. Is this a "bug" (... or did I once again got the
> documentation wrong ;-)?
bash$ groff -Tutf8 | xxd
\(bu
0000000: c2b7 0a0a 0a0a 0a0a 0a0a 0a0a 0a0a 0a0a ................
Indeed. I see this as a bug.
I find in /usr/share/groff/1.22.2/tmac/tty.tmac the following lines:
.ie c\[pc] \
. tr \[bu]\[pc]
.el \
. if c\[md] \
. tr \[bu]\[md]
If I remove them I get (correctly)
bash$ groff -Tutf8 | xxd
\(bu
0000000: e280 a20a 0a0a 0a0a 0a0a 0a0a 0a0a 0a0a ................
I don't know why these lines are there. Remapping the bullet
character if it doesn't exist might be legitimate, but in this
case it gets remapped on the condition that *another* character
exists, not that bullet *doesn't* exist. That's wrong.