[Help-bash] catching read error conditions

[Mart Frauenlob]

Hello,

I'm trying to catch two error conditions in this example script.

1. Detect if read times out. This is the only way I found that seems to 
work ( || ... after the read command). Is this correct?

2. Detect if the command inside the redirected process substitution 
fails and print a message to stderr.
What happens for me here is, that after the script exits, the prompt 
returns, but then suddenly after a while the 'failed' message turns up 
(The time varied in my tests, also using TMOUT variable). Everything 
after the || is executed and the shell hangs without a prompt. I have to 
hit return to get it back.
What am I doing wrong?

# cat read_fun
#!/bin/bash
set -x
while read -r -t 1 || \
    { (($? > 128)) && \
        printf "timeout reached\n" >&2 && break; }; \
    do :
done < <( { sleep 2 ; false; } || { printf "failed\n" >&2; exit 2; })
exit $?

# ./read_fun
+ read -r -t 1
++ sleep 2
+ (( 142 > 128 ))
+ printf 'timeout reached\n'
timeout reached
+ break
+ exit 0
# ++ false
++ printf 'failed\n'
failed
++ exit 2

<-- no prompt, have to hit return.


Best regards

Mart