Re: Bash: A Question

[Chet Ramey]

On 6/3/20 1:49 AM, Lord Sam wrote:

> It would appear that, for every four backslashes added around *"hello"* (that
> is, four on each side), the output alternates between adding *""* around
> the output expression (and keeping the amount of *\* in the output the
> same), or adding an additional *\* to the output expression (and removing
> the *""* around the output).
> 
> Why does this occur?

Because `` processing strips backslashes before certain characters, but not
others, before passing the command to a subshell, where it is parsed and
executed.

https://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_06_03

details which characters are special.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/