how to declare -n from arguments ?

[alex xmb sw ratchev]

i try , small simplifications along ..

say i have i= , then while (( ++i <= $# ))
and here i want the -n way , to test
instead n=${!i}
for one declare -n before the loop

but i cant get any code working ..

~ $ declare -n n=\!i
bash: declare: `!i': invalid variable name for name reference

declare -n n=@\[i]
bash: declare: `@[i]': invalid variable name for name reference

declare -n n=i
~ $ i=2
~ $ set 01 02 03
~ $ printf $n\\n
2

thxx for help ..
= ))