Re: how to declare -n from arguments ?

[Zachary Santer]

On Mon, Jul 8, 2024 at 7:51 PM alex xmb sw ratchev <fxmbsw7@gmail.com> wrote:
>
> ill do on func call args=( '' "$@" ) and do args and i in -n

Nothing's stopping you from doing this, if you really want to:

declare -i i=0
while (( i < ${#} )); do
  (( ++i ))
  printf '%s\n' "${@:i:1}"
done

Could easily be modified to go through arguments backwards, for
instance. Something 'for arg in "${@}"' can't do.