Re: Exit application with two function calls

[Andreas Schwab]

abi@e-arroyo.net writes:

> =====
>
> #!/bin/bash
>
> error () {
>
>    echo -e "\n\terror: ${*}\n"
>    exit;

Replace that with "exit 1".  You can use any other non-zero exit code.

>    # kill $$
>
> }
>
> check_file () {
>
>    input="$*"
>
>    if [ -e $input ]; then

This will fail if the argument contains a space.  You need to properly
quote the variable, as you did below.

>       echo "$input"
>    else
>       error "invalid directory: $input"
>    fi
>
> }
>
>
> chkFile="`check_file $1`"

Replace that with

  chkFile=`check_file "$1"` || exit

Andreas.

-- 
Andreas Schwab, SuSE Labs, schwab@suse.de
SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany
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