Re: Exit application with two function calls

[abi]

> abi@e-arroyo.net writes:
>
>> =====
>>
>> #!/bin/bash
>>
>> error () {
>>
>>    echo -e "\n\terror: ${*}\n"
>>    exit;
>
> Replace that with "exit 1".  You can use any other non-zero exit code.
>
>>    # kill $$
>>
>> }
>>
>> check_file () {
>>
>>    input="$*"
>>
>>    if [ -e $input ]; then
>
> This will fail if the argument contains a space.  You need to properly
> quote the variable, as you did below.
>
>>       echo "$input"
>>    else
>>       error "invalid directory: $input"
>>    fi
>>
>> }
>>
>>
>> chkFile="`check_file $1`"
>
> Replace that with
>
>   chkFile=`check_file "$1"` || exit
>
> Andreas.
>
> --
> Andreas Schwab, SuSE Labs, schwab@suse.de
> SuSE Linux Products GmbH, Maxfeldstraße 5, 90409 Nürnberg, Germany
> PGP key fingerprint = 58CA 54C7 6D53 942B 1756  01D3 44D5 214B 8276 4ED5
> "And now for something completely different."
>


Thanks for the response! The OR statement is an excellent solution.