Re: [Fab-user] bash variable substitution

[Vincent Fretin]

Hi,

I've just tested trunk version, same problem.
if you do:

def echo():
    run("VAR='myvar'; echo $VAR > afile")

afile is empty.

Regards
Vincent


On Fri, Jun 12, 2009 at 3:39 PM, Jeff Forcier<address@hidden> wrote:
> Hi Vincent,
>
> As far as I know that should still work correctly; it's possible
> you're seeing a bug that was fixed post-0.9a3, where there was a
> chance of output simply being dropped and not displayed. If you're
> able, I suggest grabbing the latest version of the code from Github or
> git.fabfile.org, in which the issue has been fixed.
>
> Either way, I'll try to test out your below snippet with the latest
> code sometime soon, in case there is another bug at work here :)
>
> Best,
> Jeff
>
> On Fri, Jun 12, 2009 at 3:49 AM, Vincent Fretin<address@hidden> wrote:
>> Hi,
>>
>> bash variable substitution worked in Fabric 0.1. With Fabric 0.9a3, it
>> doen't work anymore
>>
>> def echo():
>>    run("VAR='myvar'; echo $VAR")
>>
>> returns a blank line instead of myvar:
>> [host] run: VAR='myvar'; echo $VAR
>> Password for address@hidden:
>>
>> Done.
>>
>> Using bash variable was the only way I could find Fabric 0.1 to do the
>> things I wanted.
>> In fabric 0.9a3, I think I can find another way, but I have to adapt
>> all my scripts.
>>
>> Regards
>> --
>> Vincent Fretin
>>
>>
>> _______________________________________________
>> Fab-user mailing list
>> address@hidden
>> http://lists.nongnu.org/mailman/listinfo/fab-user
>>