|
| From: | Peng Yu |
| Subject: | Re: [Help-bash] stdout and stderr to two different process substitutions |
| Date: | Wed, 25 Jan 2012 08:36:22 -0600 |
> Test case:
> $ { echo STDOUT ; echo STDERR 1>&2 ;} > >(gzip > xx.gz) 2> >(tee yy 1>&2)
It is a little unclear to me how "tee yy 1>&2" works here.
If I just call "tee yy", nothing will be printed to stdout. "STDERR"
comes from stdin. How come "1>&2" redirect stdin to stderr? Thanks!
--
Regards,
Peng
| [Prev in Thread] | Current Thread | [Next in Thread] |