Re: [Help-bash] stdout and stderr to two different process substitutions

[Bob Proulx]

Greg Wooledge wrote:
> Bob Proulx wrote:
> >   Apply 2> >(tee yy), start with tee yy first.
> > 
> >              |   | --err:2-->
> >     --in:0-->|tee|
> >              |   | --out:1-->yy
> 
> But that does not.  tee inherits foo's stdout, so its out:1 arrow
> should be pointing to the /dev/fd/63 thing.  tee will open the file
> "yy" as a new FD, which is not show in your diagram at all -- it won't
> open it as stdout.

Yes!  Of course you are correct.  I was distracted by yy being an
explicit write target for tee and misdrew the picture.  My bad.

I am not going to correct post an updated drawing however.  Hopefully
the idea behind it was sufficient to accomplish goal of showing how
things are piped and plumbed together.  :-)

Bob