Re: [Help-bash] declare -i

[Chet Ramey]

On 5/9/12 4:43 PM, Bill Gradwohl wrote:

> Now I have to try to explain this to myself as to why it works. Here goes.
> 
> Everything is considered in an arithmetic context because of the -i.
> Variables inside an arithmetic context don't need the $ or ${}, so that's
> why it works. ???
> 
> If that's the case, then putting 'xyz' into an arithmetic context should
> have produced a 0 but it didn't. Therefore my analysis must be wrong.

Not necessarily.  There's the possibility that you've found a bug, or a
limitation imposed by another attribute.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/