Re: [Help-bash] declare -i

[Chet Ramey]

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On 5/9/12 5:20 PM, Dan Douglas wrote:


> But this is probably a bug:
> 
>  $ a=(1 2 3); f() { local a=(a b c); declare -ga a+=(4); declare -p a; }; f; 
> declare -p a
>  -bash: declare: `a+': not a valid identifier
>  declare -a a='([0]="a" [1]="b" [2]="c" [3]="4")'
>  declare -a a='([0]="1" [1]="2" [2]="3")'

Maybe.  ksh93 doesn't like it, either.

> 
> Most of the anomolies aren't necessarily "bugs", just undocumented or 
> conflict 
> with documented things. One is that += can unset the zeroth element in Bash 
> if 
> the index isn't given explicitly. += doesn't unset elements in any other case.

Yeah, that's a bug.  A case of a bare `a' not being treated as equivalent
to a[0] in every context.

> Another the manual doesn't mention is that negative indexes can't be used on 
> assignment, even if the array already exists (ksh can, but zsh and mksh 
> completely disagree here too):

The number of things that the manual does not mention that bash can't do
is infinite.

- -- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/
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