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From: | Chris F.A. Johnson |
Subject: | Re: [Help-bash] initialize ten variables with a loop for |
Date: | Thu, 10 Jan 2013 14:23:23 -0500 (EST) |
User-agent: | Alpine 2.00 (LMD 1167 2008-08-23) |
On Thu, 10 Jan 2013, Gerard ROBIN wrote:
Hello, I want to initialize ten variables : el1, el2, ... el10 : for i in `seq 10`; do el$i=0; done bash: el1=0: command not found bash: el2=0: command not found bash: el3=0: command not found bash: el4=0: command not found bash: el5=0: command not found bash: el6=0: command not found bash: el7=0: command not found bash: el8=0: command not found bash: el9=0: command not found bash: el10=0: command not found what is wrong in what I did? and how can I achieve that ?
eval el{1..10}=0 -- Chris F.A. Johnson, <http://cfajohnson.com/> Author: Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress) Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
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