Re: [Help-bash] initialize ten variables with a loop for

[DJ Mills]

Sounds to me like you really want an array.
And as an aside, don't use seq. It's silly.

for ((i=0; i<10; i++)); do
  el[i]=0
done

On Thu, Jan 10, 2013 at 2:18 PM, Gerard ROBIN <address@hidden> wrote:

Hello,
I want to initialize ten variables : el1, el2, ... el10 :

for i in `seq 10`; do el$i=0; done

bash: el1=0: command not found
bash: el2=0: command not found
bash: el3=0: command not found
bash: el4=0: command not found
bash: el5=0: command not found
bash: el6=0: command not found
bash: el7=0: command not found
bash: el8=0: command not found
bash: el9=0: command not found
bash: el10=0: command not found

what is wrong in what I did?

and how can I achieve that ?

Thanks.

--
Gérard