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Re: Character clearance in either end front or back
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From: |
Greg Wooledge |
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Subject: |
Re: Character clearance in either end front or back |
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Date: |
Thu, 8 Oct 2020 07:19:45 -0400 |
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User-agent: |
Mutt/1.10.1 (2018-07-13) |
On Thu, Oct 08, 2020 at 12:00:06PM +0200, Reuti wrote:
> > Am 08.10.2020 um 08:06 schrieb Budi <budikusasi@gmail.com>:
> > but merely
> > clearing \\\ as in l=foo\\\
> >
> > k=${%%\}
>
> To remove all you will need a wildcard:
>
> k=${l%%\\*}
No, that won't do it either. You need an extended glob.
shopt -s extglob
k=${l%%+(\\)}
Without extended globs, you could do it using a loop that removes one
backslash at a time, but that's obviously going to be slower.