Re: Character clearance in either end front or back

[Chris Elvidge]

On 08/10/2020 12:19 pm, Greg Wooledge wrote:
> On Thu, Oct 08, 2020 at 12:00:06PM +0200, Reuti wrote:
> > > Am 08.10.2020 um 08:06 schrieb Budi <budikusasi@gmail.com>:
> > > but merely
> > > clearing \\\  as in l=foo\\\
> > >
> > > k=${%%\}
> >
> > To remove all you will need a wildcard:
> >
> > k=${l%%\\*}
>
> No, that won't do it either.  You need an extended glob.
>
> shopt -s extglob
> k=${l%%+(\\)}
>
> Without extended globs, you could do it using a loop that removes one
> backslash at a time, but that's obviously going to be slower.

l='foo\\\'
echo ${l\\*} works for me. (bash 5.1.0)
foo

--
Chris Elvidge
England