Re: string escaping in bash

[Alex fxmbsw7 Ratchev]

me as contraverse for that no
cheers

On Fri, Mar 12, 2021 at 10:14 PM Peng Yu <pengyu.ut@gmail.com> wrote:

> Hi Eli,
>
> > Instead of doing successive, full passes as you replace each token, your
> > program e.g. /usr/bin/pengus-whitespace-only-printf might want to read
> > in the string character by character, detect whichever replacement token
> > might be there, replace it, and move on. This would retain progress
> > state, and therefore avoid processing the same tokens twice.
>
> That is exactly a solution that I sent in a follow-up email. I clearly
> defined what I meant by string escaping in the first email. Knowing
> there is not a simpler but robust solution than my implementation is
> totally fine. I want to confirm the answer is indeed "No".
>
> --
> Regards,
> Peng
>
>