Re: string escaping in bash

[Alex fxmbsw7 Ratchev]

i think i cannot succeed
the most was the v=nonexist// version

thank you

On Fri, Mar 12, 2021 at 10:41 PM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
wrote:

> thank you
>
> i may post a new version soon whenever i succeed it, i just gotta think
> more about it
>
> thank you again
>
> On Fri, Mar 12, 2021 at 10:37 PM Lawrence Velázquez <vq@larryv.me> wrote:
>
>> > On Mar 12, 2021, at 3:25 PM, Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
>> wrote:
>> >
>> > this is without keep over and does the stupid non edge cases
>> > maybe you can give me better test cases ?
>> >
>> > i=-1 res=( ) list=( '\one' '\\Two' '\\\Three' '\\\\four' '\\\\\five' )
>> > right=( '\one' '\Two' '\\Three' '\\four' '\\\five' ) ; for str in
>> > "${list[@]}" ; do str=${str//\\n/$'\n'} str=${str//\\t/$'\t'}
>> > res[++i]=${str//\\\\/\\} ; printf '%d %s %s\n' $i "${res[i]}"
>> "${right[i]}"
>> > ; done
>>
>>         bash-5.1$ str='\\n'
>>         bash-5.1$ printf '%s' "$str" | od -A n -t a -t x1
>>                    \   \   n
>>                    5c  5c  6e
>>
>> This should become '\n' (0x5c 0x6e).
>>
>>         bash-5.1$ str=${str//\\n/$'\n'}
>>         bash-5.1$ str=${str//\\t/$'\t'}
>>         bash-5.1$ str=${str//\\\\/\\}
>>         bash-5.1$ printf '%s' "$str" | od -A n -t a -t x1
>>                    \  nl
>>                    5c  0a
>>
>> --
>> vq
>>
>>