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Re: string escaping in bash


From: Alex fxmbsw7 Ratchev
Subject: Re: string escaping in bash
Date: Fri, 12 Mar 2021 21:02:08 +0100

i need some details of peng
i wanted to make test cases for the backslashes

list=( '\one' '\\Two' '\\\Three' '\\\\four' '\\\\\five' )

which should result in output of

right=( '\one' '\Two' '\\Three' '\\four' '\\\five' )

there is collision

please review and write
especially if 'right' looks right

On Fri, Mar 12, 2021 at 8:46 PM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
wrote:

> thank you, fixing it.. trying some backslash only method now [or wish..]
>
> thank you tho !
>
> On Fri, Mar 12, 2021 at 8:45 PM Lawrence Velázquez <vq@larryv.me> wrote:
>
>> > On Mar 12, 2021, at 2:28 PM, Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
>> wrote:
>> >
>> > i dunno ..thats what its supposed to give, \\ give a \
>> > so the dude wanted in his initial mail[s]
>>
>> My fault, this is what I meant to send:
>>
>> bash-5.1$ str=$'contains ^A: \1'
>> bash-5.1$ printf '%s' "$str" | od -ta -tx1
>> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp soh
>>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  01
>> 0000016
>> bash-5.1$ str=${str//\\\\/$'\1'} str=${str//\\n/$'\n'}
>> str=${str//\\t/$'\t'}
>> bash-5.1$ str=${str//$'\1'/\\}
>> bash-5.1$ printf '%s' "$str" | od -ta -tx1
>> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp   \
>>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  5c
>> 0000016
>>
>> As you can see, the SOH character (^A, \001, etc.) in the original
>> string has been mangled.
>>
>> --
>> vq
>
>


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