Re: string escaping in bash

[Alex fxmbsw7 Ratchev]

so i failed the backslash only method
there may be a method if it doesnt bug the same to replace first the
replacement of \\ then later back

till then only a nonexist string is there as place holder
ill test if i even need a place holder, hm ?

v=nonexist// i=-1 res=( ) list=( '\one' '\\Two' '\\\Three' '\\\\four'
'\\\\\five' ) right=( '\one' '\Two' '\\Three' '\\four' '\\\five' ) ; for
str in "${list[@]}" ; do str=${str//\\\\/$v} str=${str//\\n/$'\n'}
str=${str//\\t/$'\t'} res[++i]=${str//$v/\\} ; printf '%d %s %s\n' $i
"${res[i]}" "${right[i]}" ; done
0 \one \one
1 \Two \Two
2 \\Three \\Three
3 \\four \\four
4 \\\five \\\five

On Fri, Mar 12, 2021 at 9:09 PM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
wrote:

> thers just the question of \o or \bla should return in \o or o or what
>
> On Fri, Mar 12, 2021 at 9:02 PM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
> wrote:
>
>> i need some details of peng
>> i wanted to make test cases for the backslashes
>>
>> list=( '\one' '\\Two' '\\\Three' '\\\\four' '\\\\\five' )
>>
>> which should result in output of
>>
>> right=( '\one' '\Two' '\\Three' '\\four' '\\\five' )
>>
>> there is collision
>>
>> please review and write
>> especially if 'right' looks right
>>
>> On Fri, Mar 12, 2021 at 8:46 PM Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
>> wrote:
>>
>>> thank you, fixing it.. trying some backslash only method now [or wish..]
>>>
>>> thank you tho !
>>>
>>> On Fri, Mar 12, 2021 at 8:45 PM Lawrence Velázquez <vq@larryv.me> wrote:
>>>
>>>> > On Mar 12, 2021, at 2:28 PM, Alex fxmbsw7 Ratchev <fxmbsw7@gmail.com>
>>>> wrote:
>>>> >
>>>> > i dunno ..thats what its supposed to give, \\ give a \
>>>> > so the dude wanted in his initial mail[s]
>>>>
>>>> My fault, this is what I meant to send:
>>>>
>>>> bash-5.1$ str=$'contains ^A: \1'
>>>> bash-5.1$ printf '%s' "$str" | od -ta -tx1
>>>> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp soh
>>>>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  01
>>>>
>>>> 0000016
>>>> bash-5.1$ str=${str//\\\\/$'\1'} str=${str//\\n/$'\n'}
>>>> str=${str//\\t/$'\t'}
>>>> bash-5.1$ str=${str//$'\1'/\\}
>>>> bash-5.1$ printf '%s' "$str" | od -ta -tx1
>>>> 0000000    c   o   n   t   a   i   n   s  sp   ^   A   :  sp   \
>>>>            63  6f  6e  74  61  69  6e  73  20  5e  41  3a  20  5c
>>>>
>>>> 0000016
>>>>
>>>> As you can see, the SOH character (^A, \001, etc.) in the original
>>>> string has been mangled.
>>>>
>>>> --
>>>> vq
>>>
>>>