Re: case statement with non-consecutive numbers

[pauline-galea]

What other options could be available besides

for ((i=1; i <= 1000; i++)); do

Perhaps using $(seq 1 2 20)

Anything else?

> Sent: Friday, April 16, 2021 at 9:10 AM
> From: "Dennis Williamson" <dennistwilliamson@gmail.com>
> To: "help-bash" <help-bash@gnu.org>
> Subject: Re: case statement with non-consecutive numbers
>
> On Thu, Apr 15, 2021, 4:04 PM Greg Wooledge <greg@wooledge.org> wrote:
>
> > On Thu, Apr 15, 2021 at 03:57:42PM -0500, Dennis Williamson wrote:
> > > On Thu, Apr 15, 2021, 3:30 PM Greg Wooledge <greg@wooledge.org> wrote:
> > >
> > > for ((i=1; i <= 1000; i++)); do
> > >
> > >
> > > >
> > > You can also use complex range specifications in the conditional.
> > >
> > > for ((i=1; i <= 1000 || (i > 2000 && i <= 3000); i++)); do
> >
> > That'll abort the loop after 1000, unless something inside the loop
> > modifies i to jump it to 2001.
> >
>
>
>
> Oops you're right.
>
> >
>