Re: code not working ..

[alex xmb sw ratchev]

On Wed, Sep 11, 2024, 1:39 AM alex xmb sw ratchev <fxmbsw7@gmail.com> wrote:

>
>
> On Wed, Sep 11, 2024, 1:35 AM alex xmb sw ratchev <fxmbsw7@gmail.com>
> wrote:
>
>>
>>
>> On Wed, Sep 11, 2024, 1:14 AM Greg Wooledge <greg@wooledge.org> wrote:
>>
>>> On Wed, Sep 11, 2024 at 00:25:15 +0200, alex xmb sw ratchev wrote:
>>> > i got in a script
>>> >
>>> > ca=( "$@" )
>>> >   checkarg() {
>>>    !
>>> > (( $# )) &&
>>> > return 1
>>> > local IFS=$'\xff \t\n' i a
>>> > i=${IFS:0:1}
>>> >  for a ; do
>>> > [[ ${ca[*]//"$i"/'^^'} == @(#|"$i")@("$a")@(%|"$i") ]] ||
>>> > return 1
>>> >  done
>>> > return 0
>>> >   }
>>>
>>
> the solution is
> [[ $i$ca$i == $i$a$i ]]
> i think
> .. thanks and greets ..
>

i mean
[[ $i${ca//$i/other}$i == *"$i$a$i"* ]]

> checkarg 1 &&
>>> > exit
>>>
>>> This function should return 1 immediately if you give it any arguments.
>>> The function you pasted into this email is not the same one you're
>>> running.
>>>
>>
>> gmail client stripped the ! sign away it seems to me
>> i send full script
>>
>> > -- the script runs , but at checkarg 1 ( 1 is first and only arg to
>>> script
>>> > ) fails at the [[ , not returning 0
>>> >
>>> > -x says
>>> >
>>> > + ca=("$@")
>>> > + checkarg 1
>>> > + ((  1  ))
>>> > + local 'IFS=�
>>> > ' i a
>>> > + i=$'\377'
>>> > + for a in "$@"
>>> > + [[ 1 == @(#|\�)@(\1)@(%|\�) ]]
>>> > + return 1
>>> >
>>> > but why doesnt it return null ?
>>>
>>> Assuming that the function you executed actually has
>>>
>>>     (( $# )) || return 1
>>>
>>> instead of
>>>
>>>     (( $# )) && return 1
>>>
>>
>> sorry just gmail version .. code goes ! (( ..
>> btw at -x u'd see the [[ gets run
>> eg it didnt return 1 on $?
>>
>> you are trying to match the string "1" against a pattern whose first
>>> character must be "#" or $'\xff', and "1" is not either of these.  So
>>> it doesn't match the pattern.
>>>
>>
>> i thought in extglob there is # and %
>> after thinking long i think i got the solution
>> hmm nah i didnt get it
>>
>> What happens from there is anyone's guess, because you aren't showing
>>> us the right function.
>>>
>>
>> its actual code and -x from it
>> just weird the ! sign went away
>>
>> > its supposed to do : ( argslist , with arg '1' as check )
>>> > args list , flat , xff separator , with inside occurrence of xff
>>> > ==
>>> > @(either beginning of whole || or xff )
>>>
>>> Why do you believe that the "#" character is "beginning of whole"?
>>> It's not.
>>>
>>> Glob patterns are always anchored, similar to a regex with ^ at the
>>> start and $ at the end.  You don't need to put # in to serve as an
>>> anchor.  If you put # there, it's just a plain, literal character
>>> that has to be matched.
>>>
>>
>> hmm hard to code an args check like this ..
>>
>> > is xff 377 ?
>>>
>>> \xff is \0377.  They are both encodings of a byte where every bit is 1.
>>>
>>>