Re: Another question about lambdas

[Emanuel Berg]

Michael Heerdegen wrote:

> What's the result of the following expression - and why?
> Or maybe it is invalid?
>
>   (let* ((x 'l)
>          (f (lambda () x))
>          (x 'd))
>     (funcall f))

d!

Isn't this the same lambda thing again?

(setq f (lambda () x))

(funcall f) ; DNC

(setq x "marks the spot")

(funcall f) ; marks the spot too

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