How to get a concatenation of the negations with rx (ex: [^a][^b])?

[Edgar Lux]

Hello. I am trying to get this regular expression:

    "[^a][^b]"

in an easier way. I thought that I could do 

    (rx (not (seq "a" "b")))

but that got me 

    Debugger entered--Lisp error: (error "Illegal argument to rx ‘not’: (seq 
\"a\" \"b\")")

The error is very clear, but I would like to know if there is a smart way of 
achieving the same without having to type:

    (rx (seq (not "a") (not "b")))

which produces

    "[^a][^b]"

Thank you very much.

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