Re: Fsolve- add to other program

[Tatsuro MATSUOKA]

----- Original Message -----

> From: Leo07nard 
> To: help-octave
> Cc: 
> Date: 2015/8/20, Thu 03:24
> Subject: Fsolve- add to other program
> 
> Hey everone, 
> I have some functions those are functions of two state variables (Omega,
> Q). I have defined all functions by like this example : 
> muk=@(Omega,Q)  Lambda.*Omega.*(Rk(Q)-R); 
> mue=@(Omega)  Lambda.*Omega.*(R+h.*(1-R)); 
> mun=@(Omega)  Lambda*Omega*R; 
> . 
> . 
> ..... . 
> One of my variables(xe) is a solution of the equation below: 
> (exp(delta*xe)-delta*muk*xe)-((muk/mue)*(delta*mun+mue)) 
> (note I have already defined all variables and constants and all variables
> are functions of @(Omega,Q)) But of course "xe" is not defined yet 
> because
> it is the result of the equation! How can I solve this line and put the
> result (that is definitely a function of @(Omega,Q) ) in the xe to use it in
> other equations? 
> Many many thanks. 
> Loe 


I do not understand what you want to do correctly.

Do you want solve the equation 
(exp(delta*xe)-delta*muk*xe)-((muk/mue)*(delta*mun+mue))?


Are "muk", "mue", and "mun" necessary to be functions but not parameters?


Is "delta" also a parameter?

%******************
muk=Lambda.*Omega.*(Rk(Q)-R); 
mue=Lambda.*Omega.*(R+h.*(1-R)); 
mun=Lambda.*Omega.*R;

f=@(xe)  (exp(delta*xe)-delta*muk*xe)-((muk/mue)*(delta*mun+mue))

fsolve(f, 0)

%******************

The initial guess should be selected properly.

I do not know the above is what you want.

Please give us more information if the above is not what you want.

Tatsuro