Re: Fsolve- add to other program

[tmacchant]

Sorry perhaps certification issue made my reply reflect to the list with
large delay

>Also about my another post "Fsolve- add to other program"( that I saw your
kind response in my email, but I could not find it in the page to reply) , I
have some functions of (Omega, Q) and "xe" is the root of an equation
((exp(delta*xe)-delta*muk*xe)==((muk/mue)*(delta*mun+mue)) )delta is a
parameter, but others are function of (Omega,Q) so "xe" is also a function
of (Omega,Q). so your response (f=@(xe) 
(exp(delta*xe)-delta*muk*xe)-((muk/mue)*(delta*mun+mue))) could not be
correct  because f is not just a function of "xe"-[as I told in my question
muk=@(Omega,Q)  Lambda.*Omega.*(Rk(Q)-R); and so on for others. So f=(Omega,
Q,xe) ***. 
now I want to solve this equation respect to "xe" and find xe(Omega,Q).] 

If values of Omega and Q are given, are values of mue, muk and mun
determined to constants?
The parameter values of mue, muk and mun clearly depends on Omega and Q.
The equations that I shown indirectly treat variables as functions of Omega
and Q.

If you want apparently to  wrote as function of Omega and Q, 
try the below,

%******************
muk=@(Omega,Q)  Lambda.*Omega.*(Rk(Q)-R); 
mue=@(Omega)  Lambda.*Omega.*(R+h.*(1-R)); 
mun=@(Omega)  Lambda.*Omega.*R; 

f=@(xe, Omega, Q, delta) 
(exp(delta*xe)-delta*muk(Omega,Q)*xe)-((muk(Omega,Q)/mue(Omega))*(delta*mun(Omega)+mue(Omega)));

fsolve(@(xe) f (xe, Omega, Q, delta), 0)

%******************



fsolve itself solves equation of one variable (can be a vector), thus a
trick

@(xe) f (xe, Omega, Q, delta)

is  required to translate four variables function  to one variable function.  

Tatsuro



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