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From: | Doug Stewart |
Subject: | Re: displaying an image |
Date: | Sat, 12 Sep 2015 17:28:01 -0400 |
That works to give a figure but the line is straight horizontal, I don't think it represents the equation I'm trying to use. And where does the 21 come from?On Sat, Sep 12, 2015 at 1:27 PM, Ben Abbott <address@hidden> wrote:On Sep 12, 2015, at 4:20 PM, lana frankle <address@hidden> wrote:On Sat, Sep 12, 2015 at 1:00 PM, Nicholas Jankowski <address@hidden> wrote:It's not just the case-sensitive thing though because that error message shows before I try to plot. x>=-3 and x=<5 was given in the problem I'm trying to work from the book "MATLAB: An Introduction with Applications". The error shows right after I define y. My code is:well, hard to guess without seeing the actual code you're using. Note you can use a text editor or the built in editor to write your commands in a script file, (one command per line just like you'd type on the command line). then save it as a filename.m file, and you can run the script by typing 'filename'. this allows you to edit code you run more than once, get into programming, etc.On Sat, Sep 12, 2015 at 2:56 PM, lana frankle <address@hidden> wrote:On Sat, Sep 12, 2015 at 12:07 AM, Andy Buckle <address@hidden> wrote:On 12 September 2015 at 06:02, lana frankle <address@hidden> wrote:Octave is giving me the following error while I'm trying to do 2-D plotting:>> y=((x+5).^2)/(4+3*x.^2)y = 1.5625>> figure plot(X,Y)error: figure: N must be figure handle or figure numbererror: called fromfigure at line 67 column 7I'm not sure what it means. Where do I put the "N"?you are sending plot as an argument to figure. you probably want to put them on separate linesfigureplot(X,Y)The error is coming from figure, so in general you should look at the help for the figure function. like thishelp figureit explains that calling figure with an argument N is useful when you have multiple figures open and you want to switch back to one created earlier.
--/* andy buckle */now it's telling me "error: 'x' undefined near line 1 column 5".I'm not sure the code I'm entering prior to the line where I define y is exactly the same as it was yesterday (I didn't save the code in the command window) right now it'sif x>=3 and x=<5:Assuming the code above is like what you're running, you're defining x and y but trying to plot X and Y. Octave is case sensitive so those are not the same.
> right now it's> if x>=3 and x=<5:I'm not sure what you mean by this as it has nothing to do with the code listed above.if x>=-3 and x=<5:y=((x+5).^2)/(4+3*x.^2)error: 'x' undefined near line 1 column 5#and once that's resolved, I'll want to dofigureplot(X,Y)(will I need a semi-colon after figure?)Just guessing, is this what you’re trying to do?x = linspace (3, 5, 21);figurey=((x+5).^2)/(4+3*x.^2);plot (x, y)Ben
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