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From: | BOKU |
Subject: | Re: using cellfunction |
Date: | Thu, 11 May 2017 22:42:27 +0200 |
User-agent: | Mozilla/5.0 (X11; Linux x86_64; rv:45.0) Gecko/20100101 Icedove/45.6.0 |
Thank you for your response , yes I do understand, but I did already "UniformOutput", false The problem is the function, as I want to apply a function which
needs more than just the matrix from the cell x{1,1} (for
the first cell), no I need furthermore the data which are stored
in x{3,1} (for the first cell). And It seems
that I cannot index the matrix. I just dont know what cellfunction
does with the cell.. I mean if I do @mean or @(x) x-1 i could
basicly do mean(cell2mat(x)) and it's done! But if i have a {1,3}
cell array in which {1,1} is a matrix of let's say 300X300X300 and
{1,2} is a 1X12 array, and {1,3} is a an 200,120 array what
happens then. but that is exactly what i want to do I want to
applay a function to {1:end,1} with individual datas stored in
{1:end,3}. And idon't want to loop because it's incredible slow.
It takes about 20 min looping over this cell and I have several
hundreds of them. So I want to find another solution. x{1,i}=foundimfilt{i}; x{2,i}=ref{i}; x{3,i}=meanval{i};
function [y]= doit(x) idxl=x(1,1)(:,:,1)>x(3,1)(7)+0.3 | x(1,1)(:,:,1)<x(3,7)-0.3 x(1,1)(:,:,2)>x(1,3)(6)+0.3 | x(1,1)(:,:,2)<x(1,3)(6)-0.3
... &x(1,1)(:,:,3)>x(1,3)(8)+0.3 |
x(1,1)(:,:,3)<x(1,3)(8)-0.3; idxl=imcomplement(idxl); pointsel=medfilt2(idxl,[10,10]); endfunction
pointselection = cellfun(@doit, x ,"UniformOutput" ,false );
On 2017-05-11 22:11, Juan Pablo
Carbajal wrote:
On Thu, May 11, 2017 at 9:41 PM, BOKU <address@hidden> wrote:Hello, I would to apply a function to a 3x371 cell array so my question would if there is a solution to the following for i=1:numel(values) ####### wrapping elements to get access in cellfunktion ####### because cellfunction does just deliver the cellaray wrapobj{1,i}=foundimfilt{i}; ####### I hoped that it will deliver the 3x1 cell wrapobj{2,i}=ref{i}; wrapobj{3,i}=meanval{i}; endfor function [pointsel]= similarpoints(f) idxl=f(1,1)(:,:,1)>f(3,1)(7)+0.3 | f(1,1)(:,:,1)<f(3,7)-0.3& f(1,1)(:,:,2)>f(1,3)(6)+0.3 | f(1,1)(:,:,2)<f(1,3)(6)-0.3 ... ####### so that i can access the data in the &f(1,1)(:,:,3)>f(1,3)(8)+0.3 | f(1,1)(:,:,3)<f(1,3)(8)-0.3; ####### function idxl=imcomplement(idxl); pointsel=medfilt2(idxl,[10,10]); endfunction pointselection = cellfun(@similarpoints, wrapobj,"UniformOutput" ,false ); ############ but unfortunately it seems that i don't get the full cell error: f(7): out of bound 1 error: called from similarpoints at line 3 column 10 is there a solution for the indexing or the delivering the needed informations for the function. Basicly i want to apply an individual filter to every cell and I need the information stored in wrapobj{3,i} to apply it on the matrix stored in wrapobj{1,i}! wrapobj is a 3x371 cell array. i would appreciate any help on this cheers chris _______________________________________________ Help-octave mailing list address@hidden https://lists.gnu.org/mailman/listinfo/help-octaveHi, cellfun respects the size of the input, that isc = {1,4,7,10;2,5,8,11;3,6,9,12}; f=@(x) x-1; cp = cellfun (f,c)cp = 0 3 6 9 1 4 7 10 2 5 8 11 If you input is a 3x371 cell, then the output of cellfun will be a cell of the same size. If the output of the function you evaluate on each cell element is an array or cell, then you should tell cellfun that 'UniformOutput' is false, e.g.f=@(x) linspace(1,x,3); cp = cellfun (f,c,'UniformOutput', false); whos cpVariables in the current scope: Attr Name Size Bytes Class ==== ==== ==== ===== ===== cp 3x4 288 cell Total is 12 elements using 288 bytes |
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