Re: format datestr

[Dmitri A. Sergatskov]

On Sun, Jun 17, 2018 at 7:52 AM, Luca Salardi <address@hidden> wrote:

hi,
i try to code it :

ff=datestr ("23/12/2008", "dd/mm/yyyy")

but i see this error:

error: datevec: none of the standard formats match the DATE string

​You want to use datenum():

​

octave:9> ff=datenum ("23/12/2008", "dd/mm/yyyy")
ff =  733765
octave:10> str=datestr (ff, "dd/mm/yyyy")
str = 23/12/2008

​Dmitri.

--

​