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From: | Luca Salardi |
Subject: | Re: format datestr |
Date: | Sun, 17 Jun 2018 23:10:12 -0700 (MST) |
ok..now it run correctly other problem: i 've a cell (array) and i want to transform date/time cell in a serieal data c(is cell) i try it : datenum (c, "dd/mm/yyyy") but I get a matrix not an array -- Sent from: http://octave.1599824.n4.nabble.com/Octave-General-f1599825.html
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