Re: JRE not found, windows

[PhilipNienhuis]

nrjank wrote
> I have been using Octave on a WInodws 10 PC that didn't have Java
> installed. Octave is v5.1.0, zip-package-distribution.
> 
> I installed 64bit JRE (not JDK) from here:
> https://www.java.com/en/download/
> 
> reboot.  java is in the path, CLI version check gives:
> C:\>java -version
> java version "1.8.0_231"
> Java(TM) SE Runtime Environment (build 1.8.0_231-b11)
> Java HotSpot(TM) 64-Bit Server VM (build 25.231-b11, mixed mode)
> 
> checking registry, I see the following is there:
> HKEY_LOCAL_MACHINE\SOFTWARE\JavaSoft\Java Runtime Environment
> CurrentVersion --> 1.8
> 
> but in Octave I get:
> 
>>> version -java
> ans = no Java available
> 
>>> system("java -version")
> java version "1.8.0_231"
> Java(TM) SE Runtime Environment (build 1.8.0_231-b11)
> Java HotSpot(TM) 64-Bit Server VM (build 25.231-b11, mixed mode)
> ans = 0
> 
> 
> I have deleted and unzipped a fresh copy of Octave. re-ran
> 'post-install.bat' in case that did something.  No change.  I checked
> my other computers where Java works fine, and things seem identical
> from what I can see (same reg keys, same install path, etc.) The only
> difference is that Octave reports:
> 
> octave:1> version -java
> ans = Java 1.8.0_231-b11 with Oracle Corporation Java HotSpot(TM)
> 64-Bit Server VM mixed mode
> 
> what am I missing?
> 
> nickj

32- or 64-bit Octave? (you didn't say)

AFAIK the command 'system("java -version")' also works in case of a bit
width mismatch between Octave and Java as it is just a Windows command,
outside Octave.

Philip



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