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Re: Resolution exercise Octave
From: |
Francesco Potortì |
Subject: |
Re: Resolution exercise Octave |
Date: |
Tue, 21 Apr 2020 14:12:05 +0200 |
>I am trying to solve an exercise on Octave and would like some help.
>I have a matrix A (10x5) with numbers from 1 to 80 random.
>From this matrix, 5 numbers are drawn, forming matrix B (1x5).
>I need to generate another matrix (10x5), where the numbers in matrix B are
>equal to A returns the value 1 and if different, returns the value 0. How
>can I do this?
Do you need to just make it work? If yes, this is good enough and does
not require much Octave competence:
Simone Zampini:
>I think that a couple of "for" loops are enough.
>
>Check each element and place there 0 or 1.
If you need to demonstrate a good grasp on the vector operators you
should vectorialise you code. The basic step is to create a new 10x5
matrix to which matrix A should be compared.
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