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Re: [Qemu-trivial] [Qemu-devel] [PATCH] tci: Fix some unaligned memory a
From: |
Peter Maydell |
Subject: |
Re: [Qemu-trivial] [Qemu-devel] [PATCH] tci: Fix some unaligned memory accesses |
Date: |
Tue, 9 Apr 2019 18:17:15 +0100 |
On Tue, 9 Apr 2019 at 18:04, Stefan Weil <address@hidden> wrote:
>
> On 09.04.19 08:58, Richard Henderson wrote:
> > On 4/8/19 8:04 PM, Stefan Weil wrote:
> >> static tcg_target_ulong tci_read_i(uint8_t **tb_ptr)
> >> {
> >> - tcg_target_ulong value = *(tcg_target_ulong *)(*tb_ptr);
> >> + tcg_target_ulong value;
> >
> > Ideally these would use the helpers from "qemu/bswap.h", ldl_he_p(), etc.
> That would require adding a helper for tcg_target_ulong to qemu/bswap.h.
> Or tci.c would need conditional code for reading a tcg_target_ulong.
>
> Those helpers in qemu/bswap.h are also a little bit strange:
>
> - Why does lduw_he_p return an int instead of an uint16_t?
> - Why does ldsw_he_p return an int instead of an int16_t?
> - Why does ldl_he_p return an int instead of an int32_t?
Some of these are for historical reasons (ie their API was
designed in a world where the callers were typically throwing
values around in "int"s rather than carefully using exact
right-sized types). If you want to assign the results to a
uint16_t/int16_t/int32_t this will work fine (and no cast is
required).
> - Should ldl_he_p be renamed into ldsl_he_p?
> And why is ldul_he_p missing?
The assumption is that for 32-bit accesses there is no need
to care about the signedness of the load because the result
is going into a 32-bit variable anyway and so there is no
extension of any kind to be done.
> - Should ldq_he_p be renamed into lduq_he_p?
> And why is ldsq_he_p missing?
Similarly here the value is being returned as a 64-bit
quantity, so there is no question of whether it should
be sign or zero extended as it isn't being extended at all.
> Using the helpers might require nasty type casts to avoid compiler
> warnings because of signed / unsigned and size mismatches.
>
> Aren't the few memcpy statements in the TCI helpers much more direct and
> understandable?
In general, no. "memcpy is a way to do an efficient possibly-unaligned
access" is an obscure bit of knowledge. We deliberately abstract this
away into these helper functions which provide APIs which are more
clearly "we need to perform a possibly-unaligned load of a specified
endianness". (It also means that if it turns out that we would
rather use __builtin_memcpy() rather than memcpy(), as we've just
discovered we need to, then there's only one file to change rather
than many.)
thanks
-- PMM