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Re: [Taler] S, B, B^-1
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From: |
Raphael Arias |
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Subject: |
Re: [Taler] S, B, B^-1 |
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Date: |
Thu, 01 Oct 2015 09:25:15 +0200 |
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User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:31.0) Gecko/20100101 Thunderbird/31.7.0 |
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Hi,
On 09/30/2015 03:06 PM, address@hidden wrote:
> On the next to last page:
>
> "S_K(.) and B_b(.) commute" i don't think that is true..
>
> and unblinding is not the inverse of blinding (at least in RSA).
>
> All that is given is: U(S(B(X))) = S(X)
I can agree with at least the last 2 lines of this. I am not sure
about the first point.
Best regards,
Raphael
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