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| From: | dbfbr |
| Subject: | lógica |
| Date: | Fri, 03 Oct 2003 13:08:56 -0000 |
| User-agent: | eGroups-EW/0.82 |
#!/bin/bash echo -n "Digite: " read NUMERO set -xv NUM=$[ $NUMERO & 1 ] <---- porque esta atrib. retorna 0? if [ $NUM -eq 0 ] set +xv then echo "PAR" else echo "impar"; fi Muito Obrigado Dirceu
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